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# 아주대 통합설계프로젝트1 전파테크(이해영교수님) 결과1 Wireless RF system and ADS advanced education

저작시기 2011.06 |등록일 2014.10.05 | 최종수정일 2017.08.03 한글 (hwp) | 12페이지 | 가격 1,200원

## 소개글

아주대 통합설계프로젝트1 전파/RF테크 이해영 교수님 A+받은 레포트입니다.
한번도 배포된적 없는 100% 창작 자료입니다. .
RF/전파 관련 졸업작품 및 졸업프로젝트 진행중이신 분들이 참고하시면 좋은 자료입니다.
많은 도움 되시길 바랍니다.

## 목차

1. Analysis of result datas (Question & Answer)
1) explain the graph and difference of two graph
2) explain the graph
3) Show that intermodulation
4) Search P1dB point and explain the graph
5) explain the reason about difference ideal line and microstrip
6) explain the HFSS graph
2. Reference

## 본문내용

● Analysis of result datas (Question & Answer)
1. explain the graph and difference of two graph
(Explain difference between 0dBm and -30dBm of input siganl in experience 1, and analysis this graph)
(1) Data of circuit & graph
(2) Spec of design
P_1Tone : Z=50ohm, P=polar(dbmtow(0 and -30),0), Freq=1GHz
Amplifier : S21=dbpolar(15,0), S11=polar(0,0), S22=polar(0,180), S12=0
→ In the first experiment, input signal of the amplifier is 0dBm. 0dBm means that the power is 1mW by the law of dBm. And the gain of amplifier is 15dB. Decibel(dB) shows log scale of any measured value. 15dB means 15times amplificaton of input signal. So the output of the amplifier is calculated at 0dBm because 0dBm + 15dB = 15dB. But there is the saturation in the amplifier, the output is lower than 15dBm. So the red input value is 0dBm and the blue output signal is 11.8dBm.
When the input signal is -30dBm, the output is -15dBm. Because -30dBm(input) + 15dB(GAIN) = -15dBm. In the second experiment, the result is linear because output is in the linear region of the amplifier.

## 참고 자료

MICROWAVE TRANSISTOR AMPLIFIERS(2th), Guillermo Gonzalez
RF Power Amplifiers for Wireless Communications(3th), Cripps Steve C.
Microwave Engineering(3rd), David M.Pozar
www.rfdh.com
www.wikipedia.org
www.rf114.com
www.naver.com